Solve using suitable identities : (999)^{3}

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2. Polynomials

hard

Evaluate using suitable identities : $(999)^{3}$

A

$997208999$

B

$997002999$

C

$997002900$

D

$977002299$

Solution

We have

$(999)^{3}=(1000-1)^{3}$

$=(1000)^{3}-(1)^{3}-3(1000)(1)(1000-1)$

(Using Identity $VII$)

$=1000000000-1-2997000$

$=997002999$

Standard 9

Mathematics

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